So the probability that the sum is at least 5 is 2/3.

## When two dice are rolled determine the probability that the sum is at least 5?

To find the probability determine the number of successful outcomes divided by the number of possible outcomes overall. Each dice has six combinations which are independent. Therefore the number of possible outcomes will be 6*6 = 36. The probability of rolling a pair of dice whose numbers add to 5 is **4/36 = 1/9**.

## What is the probability that the sum of two dice is 5?

Probabilities for the two dice

Total | Number of combinations | Probability |
---|---|---|

2 | 1 | 2.78% |

3 | 2 | 5.56% |

4 | 3 | 8.33% |

5 | 4 |
11.11% |

## When two dice are rolled what is the probability of getting a sum of 5 or 6?

6 Sided Dice probability (worked example for two dice). Two (6-sided) dice roll probability table. Single die roll probability tables.

…

Two (6-sided) dice roll probability table.

Roll a… | Probability |
---|---|

5 | 4/36 (11.111%) |

6 | 5/36 (13.889%) |

7 | 6/36 (16.667%) |

8 | 5/36 (13.889%) |

## What is the probability of obtaining a sum of five?

There are altogether 36 possibilities. Of these ,(1,4),(2,3),(3,2),(4,1) will give a sum of 5. Hence the probability is **4/36=1/9**.

## What is the probability of rolling a sum less than 10?

That totals 8 combination out of 36 that could be ten or higher, so 8/36= 2/9. since I wanted less than ten 1-(2/9) = **7/9** probability of getting less than 10.

## What is the probability that the sum of two dice is 7?

There are 36 ways in which 2 dice can be thrown (6×6 = 36). The combinations that yield a sum of 7 are 1 + 6, 2 + 5, 3 + 4, 4 + 3, 5 + 2, and 6 + 1: 6 different combinations. Therefore, the probability of rolling a 7 is 6/36, or **1/6**.

## What is the probability of getting at least 5?

The probability of getting a 5 on each dice is **1/6**.

## What is the probability of getting at least one 5?

So the probability of rolling at least one 5 is **1–(8/9)^6 = .** **5067+**. The number of possible outcomes which have atleast 1–5, is 6+6 (1×6, and 6×1, meaning one dice gets 5 and other dice 6 different numbers and vice versa). The total possible outcomes are 6×6 I.e. 36.

## When two dice are thrown what is the probability that a total of 5 will not appear?

Solution: We use the basic formula of probability to solve the problem. Total number of outcomes when dies is thrown twice = 6 x 6 = 36. The probability that 5 will not come up either time is 25/36 and the probability that 5 will come up is **11/36**.